|Arrays in Python|
|Written by Alex Armstrong|
|Monday, 19 March 2012|
Page 2 of 2
So far everything is going according to plan. Where things start to go wrong just a little is when you attempt to push the similarities between lists and arrays one step too far. For example, suppose you want to create an array initialized to a particular value. Following the general array idiom in most languages you might write:
only to discover that this doesn't work because you can't assign to a list element that doesn't already exist.
One solution is to use the append method to add elements one by one:
This works but it only works if you need to build up the list in this particular order - which most of the time you do. When the same situation arises in two- and multi-dimensioned arrays the problem often isn't as easy to solve with append, and there is a better way.
When you create an array in other languages you can usually perform operations like:
without having to worry if a[i] already exists. In many cases the cost of this facility is that you have to declare the size of the array using a dimension statement of some sort. Python doesn't have such a facility because lists are dynamic and don't have to be "dimensioned". It is fairly easy to do the same job as a dimension statement, however, using a "comprehension".
A comprehension is roughly speaking just an expression that specifies a sequence of values - think of it as a compact for loop. In Python a comprehension can be used to generate a list.
This means that we can use a comprehension to initialize a list so that it has a predefined size. The simplest form of a list comprehension is
[expression for variable in list]
For example, to create the list equivalent of a ten-element array you could write:
myList=[0 for i in range(10)]
Following this you have a ten-element list and you can write
without any worries - as long as i<10.
You can also use the for variable in the expression. For example:
myList=[i for i in range(10)]
sets myList to [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] and
myList=[i*i for i in range(10)]
sets myList to [0, 1, 4, 9, 16, 25, 36, 49, 64, 81].
The idea is that if you want to treat a list as an array then initializing it in this way can be thought of as the Python equivalent of dimensioning the array.
It has to be said that one-dimensional arrays are fairly easy - it is when we reach two or more dimensions that mistakes are easy to make. For a programmer moving to Python the problem is that there are no explicit provisions for multidimensional arrays. As a list can contain any type of data there is no need to create a special two-dimensional data structure. All you have to do is store lists within lists - after all what is a two-dimensional array but a one-dimensional array of rows.
In Python a 2x2 array is [[1,2],[3,4]] with the list [1,2] representing the first row and the list [3,4] representing the second row. You can use slicing to index the array in the usual way. For example, if
is the list [1,2] and
is [1,2], i.e. 2.
As long as you build your arrays as nested lists in the way described then you can use slicing in the same way as you would array indexing. That is:
is the i,jth element of the array.
For example, to do something with each element in myArray you might write:
for i in range(len(myArray)):
Where len(myArray) us used to get the number of rows and len(myArray[i])) to get the number of elements in a row. Notice that there is no need for all of the rows to have the same number of elements, but if you are using a list as an array this is an assumption you need to enforce.
Notice that in the two-dimensional case the non-indexed for loop can also prove useful, but you cannot avoid a nested loop:
for row in myArray:
You can also use the index method to recover the i,j type index of an element, but you have to be careful how you do it. For example, to print the row and column index of the element:
for row in myArray:
Finally, we have the problem of initializing the array so that
doesn't generate an error. In other words, what is the two-dimensional equivalent of the dimension statement using comprehensions?
The answer is that we need to use a nested comprehension to create the list. For example, to create a 3x3 matrix we could use:
myArray=[[0 for j in range(3)] for i in range(3)]
To understand this comprehension you need to see that the inner comprehension is just:
[0 for j in range(3)]
which creates a row, and then the outer comprehension just creates a list of rows.
As before, you can use the index variables in the expression. For example:
myArray=[[i*j for j in range(3)] for i in range(3)]
In general, if you want to work with an m by n array use:
myArray=[[0 for j in range(n)] for i in range(m)]
and everything should work as you would expect.
In Python there are lots of clever ways of doing things that you generally wouldn't dream of in a lesser language. For example, a comprehension can be used to generate a list based on other lists. It is generally easy to get hold of the rows of a matrix:
for row in myArray:
but getting at the columns as lists is much more difficult. However, with the help of a comprehension it is easy to get column j as a list:
col=[row[j] for row in myArray]
Using the same idea, if you want a transpose a matrix then usually you need to write two explicit for loops but to do the job in Python you can simply write:
myArray= [[row[i] for row in myArray]
Python has lots of, usually functional, ways of working with arrays that aren't encountered in other languages. This should be enough to get you started on using lists as arrays and in more creative ways.
A Concise Introduction to Programming In Python (Book Review)
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|Last Updated ( Sunday, 29 July 2018 )|